-5t^2+50t-125=0

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Solution for -5t^2+50t-125=0 equation: 



-5t^2+50t-125=0

a = -5; b = 50; c = -125;
Δ = b2-4ac
Δ = 502-4·(-5)·(-125)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-50}{-10}=+5$

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